示例MIP1_C ++。CPP

这是我们示例的完整源代码（也可用 / /示例/ C ++ / MIP1_C ++。CPP）......
/ *版权所有2019，Gurobi优狗万app足彩化，LLC * / / *此示例制定和解决以下简单的MIP模型：最大化x + y + 2 z对x + 2 y + 3 z <= 4 x + y> = 1 x，y，z二进制* / #include使用命名空间std的“gurobi_c ++。h”;int main（int argc，char * argv []）{try {//创建环境grbenv env = grbenv（true）;env.set（“logfile”，“mip1.log”）;env.start（）;//创建一个空型号grbmodel model = grbmodel（env）;//创建变量grbvar x = model.addvar（0.0，1.0,0.0，grb_binary，“x”）;grbvar y = model.addvar（0.0，1.0,0.0，grb_binary，“y”）;GRBVAR Z = Model.addvar（0.0，1.0,0.0，Grb_binary，“Z”）;//设置目标：最大化x + y + 2 z model.setObjective（x + y + 2 * z，grb_maximize）;//添加约束：x + 2 y + 3 z <= 4 model.addconstr（x + 2 * y + 3 * z <= 4，“c0”）; // Add constraint: x + y >= 1 model.addConstr(x + y >= 1, "c1"); // Optimize model model.optimize(); cout << x.get(GRB_StringAttr_VarName) << " " << x.get(GRB_DoubleAttr_X) << endl; cout << y.get(GRB_StringAttr_VarName) << " " << y.get(GRB_DoubleAttr_X) << endl; cout << z.get(GRB_StringAttr_VarName) << " " << z.get(GRB_DoubleAttr_X) << endl; cout << "Obj: " << model.get(GRB_DoubleAttr_ObjVal) << endl; } catch(GRBException e) { cout << "Error code = " << e.getErrorCode() << endl; cout << e.getMessage() << endl; } catch(...) { cout << "Exception during optimization" << endl; } return 0; }