mip1_cs.cs.

/ *版权所有2021，Gurobi优狗万app足彩化，LLC * // *此示例制定并解决以下简单的MIP模型：最大化x + y + 2 z对x + 2 y + 3 z <= 4 x + y> = 1 x，y，z二进制* /使用系统;使用gurobi;Class MIP1_CS {静态void main（）{try {//创建空的环境，设置选项和启动grbenv ent = new grbenv（true）;env.set（“logfile”，“mip1.log”）;env.start（）;//创建空型号grbmodel model = new grbmodel（env）;//创建变量grbvar x = model.addvar（0.0，1.0,0.0，grb.binary，“x”）;grbvar y = model.addvar（0.0，1.0,0.0，grb.binary，“Y”）;grbvar z = model.addvar（0.0，1.0,0.0，grb.binary，“z”）;//设置目标：最大化x + y + 2 z model.setObjective（x + y + 2 * z，grb.maximize）; // Add constraint: x + 2 y + 3 z <= 4 model.AddConstr(x + 2 * y + 3 * z <= 4.0, "c0"); // Add constraint: x + y >= 1 model.AddConstr(x + y >= 1.0, "c1"); // Optimize model model.Optimize(); Console.WriteLine(x.VarName + " " + x.X); Console.WriteLine(y.VarName + " " + y.X); Console.WriteLine(z.VarName + " " + z.X); Console.WriteLine("Obj: " + model.ObjVal); // Dispose of model and env model.Dispose(); env.Dispose(); } catch (GRBException e) { Console.WriteLine("Error code: " + e.ErrorCode + ". " + e.Message); } } }