例子mip1_c + + . cpp
这是我们示例的完整源代码(也可在< installdir > /例子/ c++ / mip1_c + + . cpp)…
/*版权所有2022,Gurobi O狗万app足彩ptimization, LLC */ /*本例制定并解决了以下简单的MIP模型:最大化x + y + 2z受制于x + 2y + 3z <= 4 x + y >= 1 x, y, z binary */ #include "gurobi_c++.h"使用命名空间std;int main(int argc, char *argv[]) {try{//创建一个环境GRBEnv env = GRBEnv(true);env。设置(“记录文件”、“mip1.log”);env.start ();//创建一个空模型GRBModel model = GRBModel(env);//创建变量GRBVar x = model.addVar(0.0, 1.0, 0.0, GRB_BINARY， "x");GRBVar = model.addVar(0.0, 1.0, 0.0, GRB_BINARY， "y");GRBVar z = model.addVar(0.0, 1.0, 0.0, GRB_BINARY， "z");//设置目标:最大化x + y + 2z模型。setobject (x + y + 2 * z, grb_maximum); // Add constraint: x + 2 y + 3 z <= 4 model.addConstr(x + 2 * y + 3 * z <= 4, "c0"); // Add constraint: x + y >= 1 model.addConstr(x + y >= 1, "c1"); // Optimize model model.optimize(); cout << x.get(GRB_StringAttr_VarName) << " " << x.get(GRB_DoubleAttr_X) << endl; cout << y.get(GRB_StringAttr_VarName) << " " << y.get(GRB_DoubleAttr_X) << endl; cout << z.get(GRB_StringAttr_VarName) << " " << z.get(GRB_DoubleAttr_X) << endl; cout << "Obj: " << model.get(GRB_DoubleAttr_ObjVal) << endl; } catch(GRBException e) { cout << "Error code = " << e.getErrorCode() << endl; cout << e.getMessage() << endl; } catch(...) { cout << "Exception during optimization" << endl; } return 0; }
