mip1.m
mip1()函数% 2023年版权,Gurobi优化,LLC %这个狗万app足彩例子中制定和解决以下简单的MIP模型:%最大化% x + y + 2 z %, % x + 2 y + 3 z < = 4% x + y > = 1%的x, y, z的二进制名称= {“x”;“y”;' z '};模型。=稀疏([1 2 3;1 1 0]);模型。obj = [1 1 2];模型。rhs = [4; 1]; model.sense = '<>'; model.vtype = 'B'; model.modelsense = 'max'; model.varnames = names; gurobi_write(model, 'mip1.lp'); params.outputflag = 0; result = gurobi(model, params); disp(result); for v=1:length(names) fprintf('%s %d\n', names{v}, result.x(v)); end fprintf('Obj: %e\n', result.objval); end
